3b^2+4b-10=0

Solution for 3b^2+4b-10=0 equation:

3b^2+4b-10=0

a = 3; b = 4; c = -10;
Δ = b2-4ac
Δ = 42-4·3·(-10)
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{34}}{2*3}=\frac{-4-2\sqrt{34}}{6}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{34}}{2*3}=\frac{-4+2\sqrt{34}}{6}
$